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vksvks39

· started a discussion

· 1 Months ago

There is an easy method (Question: 94624.0 )

Wine Left/Initial Quantity Of wine= 343/512

As the process is repeated 3 times = 7^3/8^3

After 1st replacement ,Wine Left/Initial Quantity Of wine = 7/8

7,8 difference is 1, that is 1 quantity is 15 litre so initial quantity is 15*8= 120 litre

Question:
From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus in three attempts the ratio of wine and water became 343: 169. The initial amount of wine in the container was:
Options:
A) 75 litres
B) 100 litres
C) 150 litres
D)

120 litres

Solution:
Alternate Solution:


Knowledge Expert

· commented

· 1 Months ago

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