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Raju

· started a discussion

· 1 Months ago

27 (Question:140809.0)

Explain sir

Question:

An \(\alpha\)-particle is accelerated through a potential difference of 106 V. Its kinetic energy will be

Options:
A) 1 MeV
B)

2 MeV

C) 4 MeV
D)

8 MeV

Solution:
Ans: (b)

Knowledge Expert

· commented

· 1 Months ago

K.E=qV
=2×1.6×10−19×107J
=2×107ev
=2 Mev
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