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MAYANK SHARMA

· started a discussion

· 1 Months ago

is their any short trick or any other method available to solve such type of problem this method is very time consuming

Question:

A beats B by 100 m in a race of 1200 m and B beats C by 200 m in race of 1600 m. Approximately by how many metres can A beat C in a race of 9600 m?

Options:
A) 1600 m  
B) 1800 m
C) 1900 m
D) 2400 m
Solution:
Ans: (c)

When A cover 1200 mtr. then B will  cover 1100

Hence A will cover 1 mtr. then B will cover =\(\cfrac{1100}{1200}\) mtr.

Similarly,

When B will cover 1 mtr. then C will cover = \(\cfrac{1400}{1600}\)

When B will cover \(\cfrac{1100}{1200}\) then C will cover = \(\cfrac{1400}{1600} \times \cfrac{1100}{1200}\)

Hence when  A will cover 1 mtr. then C will cover = \(\cfrac{1400}{1600} \times \cfrac{1100}{1200}\)

Hence A will cover 9600 mtr. then C will cover  \(\cfrac{1400}{1600} \times \cfrac{1100}{1200} \times 9600\) = 7700 mtr.

Hence A beat C by = 9600 - 7700 = 1900 mtr. 

Knowledge Expert

· commented

· 1 Months ago

Only the last line is enough to answer the question, the detailed solution has been given just to understand.....If you saw the face of Shikha, then you can point out shikha anywhere in the world...Thast it....


A will cover 9600 mtr. then C will cover 1400/1600 × 1100/1200 × 9600 = 7700 mtr.

Hence A beat C by = 9600 - 7700 = 1900 mtr.

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