Detailed answer (Question: 107654.0 )

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Abhinav Sinha

· commented

· 1 Months ago

Dear student,
Please read the solution properly, S=18, 18 has been subtracted with each median A,B and C.Thus, 9,6 and 3 will come.
Best wishes.
Team TR

Kishan Kumar

By heron formula √s(s-a)(s-b)(s-c)

Akash Yadav

Gopi Rayala

root of s(s-a)(s-b)(s-c is formula of area where 2s=a+b+c

Saurav Kumar

herons formula

MRIDULA SINGH

using HERON'S FORMULA " [{s(s-a)(s-b)(s-c)}^(1/2)]" where s is semi perimeter and a,b,c are sides .

kanhaiya jha

Let a triangle is ABC.
In this triangle medians AD =12, BE =9 and CF=15.
Because the median cut each other on centroid G in the ratio of 2:1
so the segments AG= 8, GD=4, BG=6, GE=3, CG=10 and GF= 5

Now we take Triangle ABG, in this Triangle we are seeing that one side AG=8 and other side BG= 6
so the third side AB should be 10 and the triangle ABG is a right angled triangle making an angle 90 degree at the point G.

Now take a bigger triangle ABE. In this triangle we know that AG is perpendicular to BE and so the area of the Triangle ABE should be

1/2 (AG*BE)= 1/2 * 8*9 = 36

Now we know that any median of triangle bisects the triangle into two triangle of equal areas so the median BE bisects the Triangle ABC into two triangles, ABE and BED, of Equal area

so , area of ABE = area of BED = 36 so the area of triangle ABC= area of ABE+ area of BED = 36+36= 72

Detailed answer (Question: 107654.0 )

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