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Mohit yadav

· started a discussion

· 1 Months ago

Q.no.3 (Question:142965.0)

-2 is wrong answer

Question:
Minimum value of x2 + \(\cfrac{1}{x^2+1}\) – 3 is:
Options:
A) 0
B) -1
C) -3
D) -2
Solution:

x2 ≥ 0

∴ Minimum value = 0 + \(\cfrac{1}{1}\) – 3 = -2 

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct.

Regards
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