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Knowledge Expert
· commented
· 1 Months ago
heena
· commented
· 1 Months ago
Knowledge Expert
· commented
· 1 Months ago
Method 01:
a^2 + 1 = a
a^2 = a - 1
a^12 = (a - 1)^6
a^6 = (a - 1)^3
a^12 + a^6 + 1 =3
Method 02:
a^2 + 1 = a
a^2 - a + 1 = 0
a = (1 +/- i sqrt 3)/2
Complex solutions:
0.5 + 0.86603 i
0.5 - 0.86603 i
a^12 + a^6 + 1 = 3
Method 03:
a^2 - a + 1 = 0
a = (-(-1) +/- sqrt((-1)^2 - 4(1)(1))) / (2*1)
a = (1 +/- sqrt(1 - 4)) / 2
a = (1 +/- sqrt(-3)) / 2
a = 0.5 +/- sqrt(-0.75) =3
Method 04:
a power 12 plus a power 6 plus 1 equal to (-1plus a) power 6 plus (-1 plus a) power 3 plus 1 ,........ Now, apply binomial theorem for that 2 brackets