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heena

· started a discussion

· 1 Months ago

solution please

If the lengths of sides of a triangle are in 4:5:6 and inradius is 3 cm then the altitude of triangle corresponding to largest side as base is.....???

Knowledge Expert

· commented

· 1 Months ago

@heena

When the incircle of the triangle and its side are given the area of the triangle = r x s, where 'r' is the incircle and 's' is the semi-perimeter of the triangle

Now let the sides of the triangle be 4x,5x,6x respectively So the semi-perimeter (s) = (4x+5x+6x)/2 = 7.5
r = 3 (given)
So the area = 3*7.5 = 22.5

But also the area of the triangle = (6x* corresponding altitude)/2
=> 3*altitude
So the altitude = 22.5/3 = 7.5 cm

heena

· commented

· 1 Months ago

how 22.5 ?????

Knowledge Expert

· commented

· 1 Months ago

Altitude = 22.5/3 = 7.5cm

Knowledge Expert

· commented

· 1 Months ago

7.5 cm
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