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Roushan kumar

· started a discussion

· 1 Months ago

20 (Question:111639.0)

mahs

Question:

If D is a point on the side AB of triangle ABC and DE is a line through D meeting AC at E such that \(\angle\)ADE = \(\angle\)ACB, then AB. AD is equal to:

Options:
A) AE.BC
B) AC.DE
C) AE.AC
D) AB.BC
Solution:
Ans: (c)

Clearly \(\triangle\)ADE and \(\triangle\)ABC are similar


\(\therefore\) \(\cfrac{AD}{AC}=\cfrac{AE}{AB}\)

AD. AB = AE. AC

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Please specify your doubt.
Keep learning,
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