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Harpreet Singh Khangura

· started a discussion

· 1 Months ago

46 (Question:107407.0)

Not understanding this wiestion

Question:
If,


\(\cfrac{6^6+6^6+6^6+6^6+6^6+6^6}{3^6+3^6+3^6}\div\ \cfrac{\ \ \ \ \ 4^6\ +4^6+4^6+4^6}{2^6+2^6}\ \ \ \ \ =2^n\)   

 then the value of n is:

Options:
A) -1
B) 0
C) \(\cfrac{1}{2}\)
D) -2
Solution:
Ans: (b) \(\cfrac{6\times 6^6}{3\times 3^6}\times\cfrac{2\times 2^6}{4\times 4^6}\ \ = 2^n\)

\(\cfrac{6\times2^6\times 3^6\times 2\times2^6}{3\times3^6\times 4 \times 2^{12}}\)     =2n

1 = 2n ⇒ n = 0

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