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Udit Goel

· started a discussion

· 1 Months ago

answer is wrong (Question:111065.0)

when we apply componendo and dividendo ..then they cancel out each other and we get 0 as our answer

Question:
If \(sin\ \theta = \cfrac{b}{a},\) then \(\sqrt[]{\cfrac{a-b}{a+b}}+\sqrt[]{\cfrac{a+b}{a-b}}\)  is equal to:
Options:
A) 0
B) 1
C) \(\cfrac{2}{cos\ \theta}\)
D) \(\cfrac{2}{sin\ \theta}\)
Solution:
Ans: (c)

Knowledge Expert

· commented

· 1 Months ago

Dear Student, sin@=b/a 1/cosec@ = b/a a=b. cosec@ a-b = bcosec@-b = b(cosec@-1) a+b=bcosec@+b = b(cosec@+1) a+b / a-b = b(cosec@+1) / b(cosec@-1) = (cosec@+1) / (cosec@-1) Keep Learning with Us Best Wishes Team Toprankers
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