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sury nitwal

· started a discussion

· 1 Months ago

ATQ (Question:1196597.0)

difference of new number and original number = original number +27
this is the equation ATQ

Question:

In a two digit number, the digit at the unit place is 1 less than twice the digit at the ten’s place. If the digit at unit’s and ten’s place are interchanged, the difference between the new and the original number is more than the original number by 27. The original number is –  

Options:
A)

    57

B)

    24

C)

    47

D)

    35

Solution:

Ans:(c)

Let the unit place digit be y

and tens place digit be x

The number is 10x+y

Also y=2x-1..... (i) 

According to question, 

10y+x=(10x+y)+27...... (ii) 

Putting (i) on (ii) 

10(2x-1)+x=10x+2x-1+27

20x-10+x=12x+26

21x-12x=26+10

9x=36

x=4

Therefore, the number is 10(4)+{2(4)-1}=40+7=47

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Marked answer and given answer solution is correct. Please re-check.

Regards
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