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funtoos india

· started a discussion

· 1 Months ago

bakwass solution (Question:238155.0)

and code kya likh kar aa rha hai mid me

Question:
A train covers a distance of 3584 km in 2 days 8 hours. If it covers 1440 km on the first day and 1608 km on the second day, by how much does the average speed of the train for the remaining part of the journey differ from that for the entire journey?
Options:
A) 3 kmph more
B) 3 kmph less
C) 4 kmph more
D) 5 kmph less
Solution:

Remaining distance 

= (3584 -  1440-1608)km

= 536 km

Average speed of the remaining journey

\(\cfrac{536}{8}=67\) kmph

Average speed of whole journey

= \(\cfrac{3584}{56}= 64\) kmph

\(\therefore\) Required difference  = (67-64) kmph

= 3 kmph 

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· commented

· 1 Months ago

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