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arun

· started a discussion

· 1 Months ago

9/20 done by first worker i;e 1 hour=5% in 100%(20 parts) 2nd worker do
1-9/20=11/20, 11 hours equal to 55%( first worker)and remaining 45% is 2nd worker .now the work is completed then the first worker done 60% then rest is done by 2nd worker i;e 40% then the first worker do it 12/20(60%)each hour will equal to 5% then the first worker do his work in 12 hours.
am I do this is correct or wrong sir

Lalita

· started a discussion

· 1 Months ago

plz solve without taking option

Nitish Kumar

· started a discussion

· 1 Months ago

Sir, How can you say that further, they will take 5 hours to complete the work? Because it didn't mention in the question

Question:

Two workers undertake to do a job. The second worker started working 2 hours after the first. Five hours after the second worker has begun working there is still 9/20 of the work to be done. When the assignment is completed, it turns out that first worker has done 60% of the work, while second worker has done rest of the work. How many hours would take each one to do the whole job individually?

Options:
A) 10 hours and 12 hours   
B) 15 hours and 10 hours
C) 20 hours and 25 hours 
D) 18 hours and 20 hours
Solution:

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