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Sukriti

· started a discussion

· 1 Months ago

I am not getting (Question:113888.0)

Please clarify more

Question:

The product of the zeros of the polynomial at x3 - 6x2 + 11x -6  is:

Options:
A) 11
B) –6
C) 1
D) 6
Solution:
Ans: (d) Given polynomial is  x3 - 6x2 + 11x - 6.

zero of the polynomial= -(d/a) for ax3+bx2+cx+d so, 

\(=-\cfrac{(-6)}{1}=6\)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Remember formula:
The product of the zeros of the polynomial at ax^3 + bx^2 + cx + d is -(d/a).
Here, d=-6 and a=1
So, -(-6/1) = 6
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