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Tejas Mohlah

· started a discussion

· 1 Months ago

Incorrect multiplication factor with respect to time. If a and b work alternatively then in 2 minutes they would've worked for 7/24 but in the solution you have multiplied it by 3

Question:

Two pipes A and B can fill a cistern in 6 and 8 minutes  respectively. If A starts the work and they be turned on alternatively for one minute each, how long will it take to fill the cistern?

Options:
A) \(3\cfrac{3}{7}\) minutes
B) 6 minutes
C) \(6\cfrac{3}{4}\) minutes
D) \(6\cfrac{6}{7}\) minutes
Solution:
Ans: (c) Work of A and B for one minute each = \(\cfrac{1}{6}+\cfrac{1}{8}= \cfrac{7}{24}\)

Work A and B for 3 minutes each = 3 \(\times\cfrac{7}{24}=\cfrac{7}{8}\)

Total time = 3 + 3 = 6  minute

remaining part of the cistern to be filled = 1 \(- \cfrac{7}{8}=\cfrac{1}{8}\)

Time taken by A to fill \(\cfrac{1}{8}\) of the cistern = \(\cfrac{1}{8}\times6 = \cfrac{3}{4}\)

Hence, total time taken = 6 + \(\cfrac{3}{4} = 6\cfrac{3}{4}\) minutes 

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Please read the solution properly.
Keep learning,
Team TR

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