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Knowledge Expert
· commented
· 1 Months ago
Another Trick-
Tank fill by both pipe A and B in one min. = 1/36+ 1/45 = 1/20 part of the tank
If both pipes open for 7 min = 1/20 * 7 = 7/20 part.
remaining Part after 7 min = 1- (7/20) = 13/20
Tank filled by pipes A,B and c are opened at the time = (1/36 +1/45 -1/30)= 1/60 Part
1/60 part of tank filled by all pipes in one min,
Time required for fill the remaining part (13/20)= (13/20)/ 1/60
= 39 min.
I Hope you got it.