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DEV SHASHI PRAKASH

· started a discussion

· 1 Months ago

please give solution in hindi

Question:

 29 sheep can feed a uniformly growing grass in 7days and 25 sheep can feed the same in 9 days. How many sheep will be required to feed it in 6 days?

Options:
A)

 28

B)

 24

C)

 32

D)

 36

Solution:

Assuming that the grass grows at the same constant rate, regardless of whether or not sheep are grazing on it, here's an elementary solution. We, also assume that the sheep eat at the same constant rate, regardless of the amount of grass available, as long as there *is* grass available.

If no sheep are grazing on the grass, then at the end of 7 days, we would have 7*29 = 203 sheep-days' worth of grass (where one sheep-day of grass is the quantity of grass that one sheep eats in one day), and at the end of 9 days, we would have 9*25 = 225 sheep-days’ worth of grass.

Use the ordered pairs (7, 203) and (9, 225) to get a linear equation, L(x) giving the amount of grass, in sheep-days, at the end of x days.

L(x) = 11x + 126.

Then calculate L(6) = 66 +126 = 192 sheep-days worth of grass at the end of 6 days.

Then, 192/6 = 32 gives the number of sheep that can eat the 192 sheep-days worth of grass in 6 days.

Linear Method:

Let p be the rate of eating the grass and ‘b’ is the constant rate through which grass grows

29*7*p=a+7b --- (1)

25*9*p=a+9b --- (2)

=>22p=2b

=>b=11p

=>a=203p-77p=166p

n*6*p=a+6b

=>np=166p+66p

=>n=192/6 =32

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Your issue has been solved , please reattempt the question.
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