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rahul

· started a discussion

· 1 Months ago

Q. 5 (Question:115371.0)

all solution is not clear.

Question:
An ore contains 25% of an alloy that has 90% iron. Other than this, in the remaining 75% of the ore, there is no iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron?
Options:
A) 250 kg
B) 275 kg
C) 300 kg
D) 266.66 kg
Solution:
Ans: (d) In 100 kg of ore, the amount of iron \(=100\times\cfrac{25}{100}\times\cfrac{90}{100}=22.5\) kg

Now, for 22.5 kg of iron, required ore = 100 kg

for 60 kg iron, required ore \(=\cfrac{100\times60}{22.5}=266.66\)

kg

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Solution is sufficient according to the question.
Keep learning,
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