Discussions
ashwani kumar

· started a discussion

· 1 Months ago

Why we assume speed of train 2nd greater than 1st

Question:
Two trains of equal length running at different speed take ‘a’ and ‘b’ second respectively to cross a pole. Then, time taken by the trains to cross each other when they are running in the same direction is :
Options:
A) \(\cfrac{2ab}{a+b}\)
B) \(\cfrac{2n}{a+b}\)
C) \(\cfrac{2ab}{a-b}\)
D) \(\cfrac{a-b}{2ab}\)
Solution:
Ans: (c) Let, length of both the trains = x metres

Then, Speed of the first train \(=\cfrac{x}{a}m/s\)

And, speed of the second train \(=\cfrac{x}{b}m/s\)

We further assume that speed of the second train is more than that of the first train

Total distance = x + x = 2x metres 

Relative speed \(=\cfrac{x}{b}-\cfrac{x}{a}=\cfrac{(a-b)x}{ab}m/s\)

\(\therefore\) Time taken by trains to pass each other 


Knowledge Expert

· commented

· 1 Months ago

Dear student Given answer is correct In the Question Given is the running same direction, that means speed is substract. and follow the Best wishes Team TR

All Rights Reserved Top Rankers