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Arun

· started a discussion

· 1 Months ago

unclear (Question: 83318.0 )

Please explain it quite elaborately. Thank u

Question:

3 years ago the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is

Options:
A) 1 year
B) 5 years
C) 2 year
D) 3 year
Solution:

Ans: (c)

Total age of 5 members, three years ago

= 17 × 5 = 85 years


Three years hence,

 Total age of 5 members = 85+3x5 = 85+15 = 100 years


Sum of present ages of 6 members = 17 × 6 = 102 years


Present age of baby= 102 – 100 = 2 years.

Knowledge Expert

· commented

· 1 Months ago

We're told that 3 YEARS AGO, the average age of a family of 5 members was 17 years.

This means that the SUM of their ages was (5)*(17) = 85 years.

A baby was born (meaning that there are now 6 family members). We're told that the PRESENT average age of the family members is the SAME.

This means that the sum of the ages is (6)*(17) = 102 years.

We're asked for the PRESENT age of the baby.

Since each of the original 5 family members has aged 3 years since the initial average was calculated, the sum of their PRESENT ages is...

85 + (5)*(3) = 100.

Since the current sum of the 6 family members is 102, the baby is 102-100 = 2 years old.
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