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Aman Dixit

· started a discussion

· 1 Months ago

video solution (Question:96569.0)

pls provide video solution

Question:

If P = sin θ (sin θ + sin 3θ),then

Options:
A) P ≥ 0 only when θ ≥ 0
B)

P ≤ 0 for all real θ

C) P ≥ 0 for all real θ
D) P ≤ 0 only when θ ≤ 0
Solution:

We have

P = sin θ (sin θ + sin3 θ)

= sin θ (2 sin 2 θ. cos θ)


[\(\because sin C + sin D = 2 sin \left ( \cfrac {C+D}{2} \right ).cos\left ( \cfrac {C-D}{2} \right )\)]

⇒ P = sin 2 θ (2 sin θ. cos θ)

= sin 2θ sin 2θ = sin22 θ 

P = sin22 θ ≥ 0

for all real θ

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Currently it is not available but we will look towards your issue. thanks for showing your interest.
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